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x^2+2x^2=6.71^2
We move all terms to the left:
x^2+2x^2-(6.71^2)=0
We add all the numbers together, and all the variables
3x^2-45.0241=0
a = 3; b = 0; c = -45.0241;
Δ = b2-4ac
Δ = 02-4·3·(-45.0241)
Δ = 540.2892
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{540.2892}}{2*3}=\frac{0-\sqrt{540.2892}}{6} =-\frac{\sqrt{}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{540.2892}}{2*3}=\frac{0+\sqrt{540.2892}}{6} =\frac{\sqrt{}}{6} $
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